(3x-2)^2=1/4

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Solution for (3x-2)^2=1/4 equation:


x in (-oo:+oo)

(3*x-2)^2 = 1/4 // - 1/4

(3*x-2)^2-(1/4) = 0

(3*x-2)^2-1/4 = 0

(4*(3*x-2)^2)/4-1/4 = 0

4*(3*x-2)^2-1 = 0

36*x^2-48*x+15 = 0

36*x^2-48*x+15 = 0

3*(12*x^2-16*x+5) = 0

12*x^2-16*x+5 = 0

DELTA = (-16)^2-(4*5*12)

DELTA = 16

DELTA > 0

x = (16^(1/2)+16)/(2*12) or x = (16-16^(1/2))/(2*12)

x = 5/6 or x = 1/2

3*(x-1/2)*(x-5/6) = 0

(3*(x-1/2)*(x-5/6))/4 = 0

(3*(x-1/2)*(x-5/6))/4 = 0 // * 4

3*(x-1/2)*(x-5/6) = 0

( 3 )

3 = 0

x belongs to the empty set

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

( x-5/6 )

x-5/6 = 0 // + 5/6

x = 5/6

x in { 1/2, 5/6 }

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